13134350035 has 4 divisors (see below), whose sum is σ = 15761220048. Its totient is φ = 10507480024.

The previous prime is 13134350029. The next prime is 13134350081. The reversal of 13134350035 is 53005343131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13134350035 - 2³ = 13134350027 is a prime.

It is a super-2 number, since 2×13134350035² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13134349985 and 13134350012.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1313434999 + ... + 1313435008.

It is an arithmetic number, because the mean of its divisors is an integer number (3940305012).

Almost surely, 2^13134350035 is an apocalyptic number.

13134350035 is a deficient number, since it is larger than the sum of its proper divisors (2626870013).

13134350035 is an equidigital number, since it uses as much as digits as its factorization.

13134350035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2626870012.

The product of its (nonzero) digits is 8100, while the sum is 28.

Adding to 13134350035 its reverse (53005343131), we get a palindrome (66139693166).

The spelling of 13134350035 in words is "thirteen billion, one hundred thirty-four million, three hundred fifty thousand, thirty-five".