131344033211331 has 8 divisors (see below), whose sum is σ = 175125595979280. Its totient is φ = 87562579625472.

The previous prime is 131344033211291. The next prime is 131344033211341. The reversal of 131344033211331 is 133112330443131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131344033211331 - 2¹⁷ = 131344033080259 is a prime.

It is a super-2 number, since 2×131344033211331² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131344033211292 and 131344033211301.

It is not an unprimeable number, because it can be changed into a prime (131344033211341) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24446070 + ... + 29330843.

It is an arithmetic number, because the mean of its divisors is an integer number (21890699497410).

Almost surely, 2^{131344033211331} is an apocalyptic number.

131344033211331 is a deficient number, since it is larger than the sum of its proper divisors (43781562767949).

131344033211331 is an equidigital number, since it uses as much as digits as its factorization.

131344033211331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54591045.

The product of its (nonzero) digits is 23328, while the sum is 33.

Adding to 131344033211331 its reverse (133112330443131), we get a palindrome (264456363654462).

The spelling of 131344033211331 in words is "one hundred thirty-one trillion, three hundred forty-four billion, thirty-three million, two hundred eleven thousand, three hundred thirty-one".