Search a number
-
+
1313441122403 = 4129318101507
BaseRepresentation
bin10011000111001111001…
…100010000100001100011
311122120012222012012212102
4103013033030100201203
5133004411411404103
62443215253321015
7163615203222224
oct23071714204143
94576188165772
101313441122403
114670332aa413
1219267893616b
1396b1a9a80c7
14477dc74124b
1524273e5ee88
hex131cf310863

1313441122403 has 4 divisors (see below), whose sum is σ = 1313759228040. Its totient is φ = 1313123016768.

The previous prime is 1313441122397. The next prime is 1313441122421. The reversal of 1313441122403 is 3042211443131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313441122403 - 230 = 1312367380579 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313441122453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159046625 + ... + 159054882.

It is an arithmetic number, because the mean of its divisors is an integer number (328439807010).

Almost surely, 21313441122403 is an apocalyptic number.

1313441122403 is a deficient number, since it is larger than the sum of its proper divisors (318105637).

1313441122403 is an equidigital number, since it uses as much as digits as its factorization.

1313441122403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 318105636.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1313441122403 its reverse (3042211443131), we get a palindrome (4355652565534).

The spelling of 1313441122403 in words is "one trillion, three hundred thirteen billion, four hundred forty-one million, one hundred twenty-two thousand, four hundred three".

Divisors: 1 4129 318101507 1313441122403