Base | Representation |
---|---|
bin | 11101110111010011111101… |
… | …011001111011101001011011 |
3 | 122020001101201200020112000101 |
4 | 131313103331121323221123 |
5 | 114203421212421021433 |
6 | 1143202432332520231 |
7 | 36444213316456531 |
oct | 3567237531735133 |
9 | 566041650215011 |
10 | 131344351345243 |
11 | 38939910215553 |
12 | 128934b9620077 |
13 | 583994708ab7a |
14 | 2461159ba6151 |
15 | 102b87becd07d |
hex | 7774fd67ba5b |
131344351345243 has 4 divisors (see below), whose sum is σ = 131344414529688. Its totient is φ = 131344288160800.
The previous prime is 131344351345237. The next prime is 131344351345267. The reversal of 131344351345243 is 342543153443131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131344351345243 - 237 = 131206912391771 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131344351345193 and 131344351345202.
It is not an unprimeable number, because it can be changed into a prime (131344331345243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28364158 + ... + 32668243.
It is an arithmetic number, because the mean of its divisors is an integer number (32836103632422).
Almost surely, 2131344351345243 is an apocalyptic number.
131344351345243 is a deficient number, since it is larger than the sum of its proper divisors (63184445).
131344351345243 is an equidigital number, since it uses as much as digits as its factorization.
131344351345243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63184444.
The product of its digits is 3110400, while the sum is 46.
The spelling of 131344351345243 in words is "one hundred thirty-one trillion, three hundred forty-four billion, three hundred fifty-one million, three hundred forty-five thousand, two hundred forty-three".
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