Base | Representation |
---|---|
bin | 11000011101110010… |
… | …00100001111010011 |
3 | 1020220101100001101211 |
4 | 30032321010033103 |
5 | 203344443224413 |
6 | 10011203040551 |
7 | 643330316602 |
oct | 141671041723 |
9 | 36811301354 |
10 | 13134742483 |
11 | 5630246485 |
12 | 2666970157 |
13 | 131428ac95 |
14 | 8c8601a39 |
15 | 51d1ba83d |
hex | 30ee443d3 |
13134742483 has 4 divisors (see below), whose sum is σ = 13319738928. Its totient is φ = 12949746040.
The previous prime is 13134742459. The next prime is 13134742499. The reversal of 13134742483 is 38424743131.
13134742483 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 38424743131 = 4157 ⋅9243383.
It is a cyclic number.
It is not a de Polignac number, because 13134742483 - 217 = 13134611411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13134742433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92498116 + ... + 92498257.
It is an arithmetic number, because the mean of its divisors is an integer number (3329934732).
Almost surely, 213134742483 is an apocalyptic number.
13134742483 is a deficient number, since it is larger than the sum of its proper divisors (184996445).
13134742483 is an equidigital number, since it uses as much as digits as its factorization.
13134742483 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 184996444.
The product of its digits is 193536, while the sum is 40.
The spelling of 13134742483 in words is "thirteen billion, one hundred thirty-four million, seven hundred forty-two thousand, four hundred eighty-three".
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