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1313516353 = 1327989839
BaseRepresentation
bin100111001001010…
…1010101101000001
310101112121112200211
41032102222231001
510142230010403
6334201114121
744356463512
oct11622525501
93345545624
101313516353
1161449a306
12307a88941
1317c18b216
14c663ca09
157a4b006d
hex4e4aab41

1313516353 has 4 divisors (see below), whose sum is σ = 1314507520. Its totient is φ = 1312525188.

The previous prime is 1313516311. The next prime is 1313516371. The reversal of 1313516353 is 3536153131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313516353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313516753) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 493593 + ... + 496246.

It is an arithmetic number, because the mean of its divisors is an integer number (328626880).

Almost surely, 21313516353 is an apocalyptic number.

It is an amenable number.

1313516353 is a deficient number, since it is larger than the sum of its proper divisors (991167).

1313516353 is an equidigital number, since it uses as much as digits as its factorization.

1313516353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 991166.

The product of its digits is 12150, while the sum is 31.

The square root of 1313516353 is about 36242.4661550508. The cubic root of 1313516353 is about 1095.1623239546.

Adding to 1313516353 its reverse (3536153131), we get a palindrome (4849669484).

The spelling of 1313516353 in words is "one billion, three hundred thirteen million, five hundred sixteen thousand, three hundred fifty-three".

Divisors: 1 1327 989839 1313516353