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1313622323347 = 12739726054113
BaseRepresentation
bin10011000111011001111…
…111011111000010010011
311122120200121011011211111
4103013121333133002103
5133010244303321342
62443245245154151
7163622533341655
oct23073177370223
94576617134744
101313622323347
11467116612364
1219270955b957
1396b493ac7b9
144781882c6d5
1524284d04217
hex131d9fdf093

1313622323347 has 8 divisors (see below), whose sum is σ = 1327300783616. Its totient is φ = 1299995972352.

The previous prime is 1313622323333. The next prime is 1313622323353. The reversal of 1313622323347 is 7433232263131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313622323347 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313622323327) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12976638 + ... + 13077475.

It is an arithmetic number, because the mean of its divisors is an integer number (165912597952).

Almost surely, 21313622323347 is an apocalyptic number.

1313622323347 is a deficient number, since it is larger than the sum of its proper divisors (13678460269).

1313622323347 is a wasteful number, since it uses less digits than its factorization.

1313622323347 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26054637.

The product of its digits is 326592, while the sum is 40.

Adding to 1313622323347 its reverse (7433232263131), we get a palindrome (8746854586478).

The spelling of 1313622323347 in words is "one trillion, three hundred thirteen billion, six hundred twenty-two million, three hundred twenty-three thousand, three hundred forty-seven".

Divisors: 1 127 397 50419 26054113 3308872351 10343482861 1313622323347