Base | Representation |
---|---|
bin | 10011000111011011010… |
… | …100010010001100110011 |
3 | 11122120202010222120012101 |
4 | 103013123110102030303 |
5 | 133010321001144021 |
6 | 2443251401441231 |
7 | 163623223315330 |
oct | 23073324221463 |
9 | 4576663876171 |
10 | 1313644553011 |
11 | 46712811588a |
12 | 192714aa0217 |
13 | 96b50b93a4b |
14 | 4781b777987 |
15 | 24286c45a91 |
hex | 131db512333 |
1313644553011 has 4 divisors (see below), whose sum is σ = 1501308060592. Its totient is φ = 1125981045432.
The previous prime is 1313644552993. The next prime is 1313644553063. The reversal of 1313644553011 is 1103554463131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1313644553011 - 233 = 1305054618419 is a prime.
It is a super-2 number, since 2×13136445530112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1313644554011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93831753780 + ... + 93831753793.
It is an arithmetic number, because the mean of its divisors is an integer number (375327015148).
Almost surely, 21313644553011 is an apocalyptic number.
1313644553011 is a deficient number, since it is larger than the sum of its proper divisors (187663507581).
1313644553011 is an equidigital number, since it uses as much as digits as its factorization.
1313644553011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 187663507580.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 1313644553011 in words is "one trillion, three hundred thirteen billion, six hundred forty-four million, five hundred fifty-three thousand, eleven".
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