Base | Representation |
---|---|
bin | 10011000111110001010… |
… | …010111111010110111001 |
3 | 11122121200211212111001001 |
4 | 103013301102333112321 |
5 | 133012044401444231 |
6 | 2443352133325001 |
7 | 163635321603604 |
oct | 23076122772671 |
9 | 4577624774031 |
10 | 1314013312441 |
11 | 4672a7293245 |
12 | 1927b8496761 |
13 | 96bac3b77ab |
14 | 4785472933b |
15 | 242a92d7b61 |
hex | 131f14bf5b9 |
1314013312441 has 4 divisors (see below), whose sum is σ = 1317047985652. Its totient is φ = 1310978639232.
The previous prime is 1314013312387. The next prime is 1314013312459. The reversal of 1314013312441 is 1442133104131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 314805155625 + 999208156816 = 561075^2 + 999604^2 .
It is a cyclic number.
It is not a de Polignac number, because 1314013312441 - 221 = 1314011215289 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1314013312481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1517335956 + ... + 1517336821.
It is an arithmetic number, because the mean of its divisors is an integer number (329261996413).
Almost surely, 21314013312441 is an apocalyptic number.
It is an amenable number.
1314013312441 is a deficient number, since it is larger than the sum of its proper divisors (3034673211).
1314013312441 is an equidigital number, since it uses as much as digits as its factorization.
1314013312441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3034673210.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 1314013312441 its reverse (1442133104131), we get a palindrome (2756146416572).
The spelling of 1314013312441 in words is "one trillion, three hundred fourteen billion, thirteen million, three hundred twelve thousand, four hundred forty-one".
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