131402302431041 has 4 divisors (see below), whose sum is σ = 131402470363584. Its totient is φ = 131402134498500.

The previous prime is 131402302431013. The next prime is 131402302431067. The reversal of 131402302431041 is 140134203204131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131402302431041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131402302430995 and 131402302431013.

It is not an unprimeable number, because it can be changed into a prime (131402302431341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82787045 + ... + 84359346.

It is an arithmetic number, because the mean of its divisors is an integer number (32850617590896).

Almost surely, 2^{131402302431041} is an apocalyptic number.

It is an amenable number.

131402302431041 is a deficient number, since it is larger than the sum of its proper divisors (167932543).

131402302431041 is an equidigital number, since it uses as much as digits as its factorization.

131402302431041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 167932542.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 131402302431041 its reverse (140134203204131), we get a palindrome (271536505635172).

The spelling of 131402302431041 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred two million, four hundred thirty-one thousand, forty-one".