Search a number
-
+
131402312131 = 473327763007
BaseRepresentation
bin111101001100000110…
…0000010100111000011
3110120011122122002020011
41322120030002213003
54123102442442011
6140210531325351
712331162136626
oct1723014024703
9416148562204
10131402312131
11508001a7a82
1221572450857
13c51158281c
14650781ddbd
153641013621
hex1e983029c3

131402312131 has 4 divisors (see below), whose sum is σ = 131430079872. Its totient is φ = 131374544392.

The previous prime is 131402312123. The next prime is 131402312143. The reversal of 131402312131 is 131213204131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131402312131 - 23 = 131402312123 is a prime.

It is a super-2 number, since 2×1314023121312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131402310131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13876771 + ... + 13886236.

It is an arithmetic number, because the mean of its divisors is an integer number (32857519968).

Almost surely, 2131402312131 is an apocalyptic number.

131402312131 is a deficient number, since it is larger than the sum of its proper divisors (27767741).

131402312131 is an equidigital number, since it uses as much as digits as its factorization.

131402312131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27767740.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 131402312131 its reverse (131213204131), we get a palindrome (262615516262).

The spelling of 131402312131 in words is "one hundred thirty-one billion, four hundred two million, three hundred twelve thousand, one hundred thirty-one".

Divisors: 1 4733 27763007 131402312131