Base | Representation |
---|---|
bin | 1011111100110111001011… |
… | …0111011110110010100011 |
3 | 1201112012020100221120101201 |
4 | 2333031302313132302203 |
5 | 3210242143404330443 |
6 | 43540312253142031 |
7 | 2524231126002124 |
oct | 277156267366243 |
9 | 51465210846351 |
10 | 13140232105123 |
11 | 4206817504952 |
12 | 15827b918a917 |
13 | 744170665906 |
14 | 335dc23d204b |
15 | 17bc1a95534d |
hex | bf372ddeca3 |
13140232105123 has 4 divisors (see below), whose sum is σ = 13140847853568. Its totient is φ = 13139616356680.
The previous prime is 13140232105103. The next prime is 13140232105153. The reversal of 13140232105123 is 32150123204131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13140232105123 - 237 = 13002793151651 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13140232105091 and 13140232105100.
It is not an unprimeable number, because it can be changed into a prime (13140232105103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 307842211 + ... + 307884892.
It is an arithmetic number, because the mean of its divisors is an integer number (3285211963392).
Almost surely, 213140232105123 is an apocalyptic number.
13140232105123 is a deficient number, since it is larger than the sum of its proper divisors (615748445).
13140232105123 is an equidigital number, since it uses as much as digits as its factorization.
13140232105123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 615748444.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 13140232105123 its reverse (32150123204131), we get a palindrome (45290355309254).
The spelling of 13140232105123 in words is "thirteen trillion, one hundred forty billion, two hundred thirty-two million, one hundred five thousand, one hundred twenty-three".
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