13140232105411 has 4 divisors (see below), whose sum is σ = 13140239781424. Its totient is φ = 13140224429400.

The previous prime is 13140232105387. The next prime is 13140232105433. The reversal of 13140232105411 is 11450123204131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13140232105411 - 2⁹ = 13140232104899 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13140232105411.

It is not an unprimeable number, because it can be changed into a prime (13140232105811) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27541 + ... + 5126521.

It is an arithmetic number, because the mean of its divisors is an integer number (3285059945356).

Almost surely, 2^{13140232105411} is an apocalyptic number.

13140232105411 is a deficient number, since it is larger than the sum of its proper divisors (7676013).

13140232105411 is an equidigital number, since it uses as much as digits as its factorization.

13140232105411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7676012.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 13140232105411 its reverse (11450123204131), we get a palindrome (24590355309542).

The spelling of 13140232105411 in words is "thirteen trillion, one hundred forty billion, two hundred thirty-two million, one hundred five thousand, four hundred eleven".