Base | Representation |
---|---|
bin | 1011111100110111001101… |
… | …0111010100111110101001 |
3 | 1201112012020221122201021112 |
4 | 2333031303113110332221 |
5 | 3210242203024003140 |
6 | 43540313152120105 |
7 | 2524231256652422 |
oct | 277156327247651 |
9 | 51465227581245 |
10 | 13140240453545 |
11 | 4206821197177 |
12 | 15827bbb36035 |
13 | 7441722c97ca |
14 | 335dc3566649 |
15 | 17bc1b553c65 |
hex | bf3735d4fa9 |
13140240453545 has 4 divisors (see below), whose sum is σ = 15768288544260. Its totient is φ = 10512192362832.
The previous prime is 13140240453497. The next prime is 13140240453551. The reversal of 13140240453545 is 54535404204131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7945610889616 + 5194629563929 = 2818796^2 + 2279173^2 .
It is a cyclic number.
It is not a de Polignac number, because 13140240453545 - 226 = 13140173344681 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1314024045350 + ... + 1314024045359.
It is an arithmetic number, because the mean of its divisors is an integer number (3942072136065).
Almost surely, 213140240453545 is an apocalyptic number.
It is an amenable number.
13140240453545 is a deficient number, since it is larger than the sum of its proper divisors (2628048090715).
13140240453545 is an equidigital number, since it uses as much as digits as its factorization.
13140240453545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2628048090714.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 13140240453545 its reverse (54535404204131), we get a palindrome (67675644657676).
The spelling of 13140240453545 in words is "thirteen trillion, one hundred forty billion, two hundred forty million, four hundred fifty-three thousand, five hundred forty-five".
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