Base | Representation |
---|---|
bin | 11101111000001010100101… |
… | …011000001011000111010001 |
3 | 122020021000010021121200200102 |
4 | 131320022211120023013101 |
5 | 114210401323013001231 |
6 | 1143245412351302145 |
7 | 36451360636204622 |
oct | 3570124530130721 |
9 | 566230107550612 |
10 | 131403004031441 |
11 | 3896177911982a |
12 | 128a294821a955 |
13 | 584233365554c |
14 | 2463d2173da49 |
15 | 102d1612e6acb |
hex | 7782a560b1d1 |
131403004031441 has 4 divisors (see below), whose sum is σ = 131404126569984. Its totient is φ = 131401881492900.
The previous prime is 131403004031437. The next prime is 131403004031461. The reversal of 131403004031441 is 144130400304131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131403004031441 - 22 = 131403004031437 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131403004031461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 561093665 + ... + 561327806.
It is an arithmetic number, because the mean of its divisors is an integer number (32851031642496).
Almost surely, 2131403004031441 is an apocalyptic number.
It is an amenable number.
131403004031441 is a deficient number, since it is larger than the sum of its proper divisors (1122538543).
131403004031441 is a wasteful number, since it uses less digits than its factorization.
131403004031441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1122538542.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 131403004031441 its reverse (144130400304131), we get a palindrome (275533404335572).
The spelling of 131403004031441 in words is "one hundred thirty-one trillion, four hundred three billion, four million, thirty-one thousand, four hundred forty-one".
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