Base | Representation |
---|---|
bin | 11101111000001010100101… |
… | …011001101111101001001011 |
3 | 122020021000010022101121112011 |
4 | 131320022211121233221023 |
5 | 114210401323114140321 |
6 | 1143245412404200351 |
7 | 36451360642541254 |
oct | 3570124531575113 |
9 | 566230108347464 |
10 | 131403004443211 |
11 | 38961779380136 |
12 | 128a29483990b7 |
13 | 584233376aab7 |
14 | 2463d21809b2b |
15 | 102d161378ae1 |
hex | 7782a566fa4b |
131403004443211 has 4 divisors (see below), whose sum is σ = 131403028509424. Its totient is φ = 131402980377000.
The previous prime is 131403004443143. The next prime is 131403004443241. The reversal of 131403004443211 is 112344400304131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131403004443211 - 215 = 131403004410443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131403004443241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 527161 + ... + 16219861.
It is an arithmetic number, because the mean of its divisors is an integer number (32850757127356).
Almost surely, 2131403004443211 is an apocalyptic number.
131403004443211 is a deficient number, since it is larger than the sum of its proper divisors (24066213).
131403004443211 is an equidigital number, since it uses as much as digits as its factorization.
131403004443211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24066212.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 131403004443211 its reverse (112344400304131), we get a palindrome (243747404747342).
The spelling of 131403004443211 in words is "one hundred thirty-one trillion, four hundred three billion, four million, four hundred forty-three thousand, two hundred eleven".
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