Base | Representation |
---|---|
bin | 1011111100110111011110… |
… | …1100000101100110011001 |
3 | 1201112012110000011200101202 |
4 | 2333031313230011212121 |
5 | 3210242330112120231 |
6 | 43540324303123545 |
7 | 2524233130432160 |
oct | 277156754054631 |
9 | 51465400150352 |
10 | 13140313004441 |
11 | 420685913a797 |
12 | 15828202a35b5 |
13 | 74418434c42c |
14 | 335dcd0503d7 |
15 | 17bc22ad55cb |
hex | bf377b05999 |
13140313004441 has 8 divisors (see below), whose sum is σ = 15017524082304. Its totient is φ = 11263107803040.
The previous prime is 13140313004419. The next prime is 13140313004447. The reversal of 13140313004441 is 14440031304131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13140313004441 - 222 = 13140308810137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13140313004447) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5572796 + ... + 7572098.
It is an arithmetic number, because the mean of its divisors is an integer number (1877190510288).
Almost surely, 213140313004441 is an apocalyptic number.
It is an amenable number.
13140313004441 is a deficient number, since it is larger than the sum of its proper divisors (1877211077863).
13140313004441 is an equidigital number, since it uses as much as digits as its factorization.
13140313004441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2938231.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 13140313004441 its reverse (14440031304131), we get a palindrome (27580344308572).
The spelling of 13140313004441 in words is "thirteen trillion, one hundred forty billion, three hundred thirteen million, four thousand, four hundred forty-one".
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