Base | Representation |
---|---|
bin | 1011111100110111011110… |
… | …1111111011101010010001 |
3 | 1201112012110002001212221001 |
4 | 2333031313233323222101 |
5 | 3210242330341343210 |
6 | 43540324340502001 |
7 | 2524233142130434 |
oct | 277156757735221 |
9 | 51465402055831 |
10 | 13140314012305 |
11 | 4206859768a37 |
12 | 15828206aa901 |
13 | 7441846130bc |
14 | 335dcd23381b |
15 | 17bc22c3403a |
hex | bf377bfba91 |
13140314012305 has 16 divisors (see below), whose sum is σ = 16454962422144. Its totient is φ = 10054583249920.
The previous prime is 13140314012303. The next prime is 13140314012317. The reversal of 13140314012305 is 50321041304131.
It is not a de Polignac number, because 13140314012305 - 21 = 13140314012303 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13140314012303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1588816 + ... + 5367025.
It is an arithmetic number, because the mean of its divisors is an integer number (1028435151384).
Almost surely, 213140314012305 is an apocalyptic number.
It is an amenable number.
13140314012305 is a deficient number, since it is larger than the sum of its proper divisors (3314648409839).
13140314012305 is a wasteful number, since it uses less digits than its factorization.
13140314012305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6972296.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 13140314012305 its reverse (50321041304131), we get a palindrome (63461355316436).
The spelling of 13140314012305 in words is "thirteen trillion, one hundred forty billion, three hundred fourteen million, twelve thousand, three hundred five".
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