131403244144033 has 4 divisors (see below), whose sum is σ = 138319204362160. Its totient is φ = 124487283925908.

The previous prime is 131403244143967. The next prime is 131403244144049. The reversal of 131403244144033 is 330441442304131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131403244144033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131403244143983 and 131403244144001.

It is not an unprimeable number, because it can be changed into a prime (131403244444033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3457980109035 + ... + 3457980109072.

It is an arithmetic number, because the mean of its divisors is an integer number (34579801090540).

Almost surely, 2^{131403244144033} is an apocalyptic number.

It is an amenable number.

131403244144033 is a deficient number, since it is larger than the sum of its proper divisors (6915960218127).

131403244144033 is an equidigital number, since it uses as much as digits as its factorization.

131403244144033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6915960218126.

The product of its (nonzero) digits is 165888, while the sum is 37.

Adding to 131403244144033 its reverse (330441442304131), we get a palindrome (461844686448164).

The spelling of 131403244144033 in words is "one hundred thirty-one trillion, four hundred three billion, two hundred forty-four million, one hundred forty-four thousand, thirty-three".