13140331143131 has 4 divisors (see below), whose sum is σ = 13142037909000. Its totient is φ = 13138624377264.

The previous prime is 13140331143019. The next prime is 13140331143161. The reversal of 13140331143131 is 13134113304131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13140331143131 - 2¹⁸ = 13140330880987 is a prime.

It is a super-2 number, since 2×13140331143131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13140331143094 and 13140331143103.

It is not an unprimeable number, because it can be changed into a prime (13140331143161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 853371386 + ... + 853386783.

It is an arithmetic number, because the mean of its divisors is an integer number (3285509477250).

Almost surely, 2^{13140331143131} is an apocalyptic number.

13140331143131 is a deficient number, since it is larger than the sum of its proper divisors (1706765869).

13140331143131 is an equidigital number, since it uses as much as digits as its factorization.

13140331143131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1706765868.

The product of its (nonzero) digits is 3888, while the sum is 29.

Adding to 13140331143131 its reverse (13134113304131), we get a palindrome (26274444447262).

The spelling of 13140331143131 in words is "thirteen trillion, one hundred forty billion, three hundred thirty-one million, one hundred forty-three thousand, one hundred thirty-one".