131403352511451 has 4 divisors (see below), whose sum is σ = 175204470015272. Its totient is φ = 87602235007632.

The previous prime is 131403352511449. The next prime is 131403352511461. The reversal of 131403352511451 is 154115253304131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 131403352511451 - 2¹ = 131403352511449 is a prime.

It is a super-2 number, since 2×131403352511451² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131403352511461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21900558751906 + ... + 21900558751911.

It is an arithmetic number, because the mean of its divisors is an integer number (43801117503818).

Almost surely, 2^{131403352511451} is an apocalyptic number.

131403352511451 is a deficient number, since it is larger than the sum of its proper divisors (43801117503821).

131403352511451 is an equidigital number, since it uses as much as digits as its factorization.

131403352511451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43801117503820.

The product of its (nonzero) digits is 108000, while the sum is 39.

The spelling of 131403352511451 in words is "one hundred thirty-one trillion, four hundred three billion, three hundred fifty-two million, five hundred eleven thousand, four hundred fifty-one".