13140351131 has 4 divisors (see below), whose sum is σ = 13166685000. Its totient is φ = 13114017264.

The previous prime is 13140351101. The next prime is 13140351167. The reversal of 13140351131 is 13115304131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13140351131 - 2¹⁴ = 13140334747 is a prime.

It is a super-2 number, since 2×13140351131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13140351097 and 13140351106.

It is not an unprimeable number, because it can be changed into a prime (13140351101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13166186 + ... + 13167183.

It is an arithmetic number, because the mean of its divisors is an integer number (3291671250).

Almost surely, 2^13140351131 is an apocalyptic number.

13140351131 is a deficient number, since it is larger than the sum of its proper divisors (26333869).

13140351131 is an equidigital number, since it uses as much as digits as its factorization.

13140351131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26333868.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 13140351131 its reverse (13115304131), we get a palindrome (26255655262).

The spelling of 13140351131 in words is "thirteen billion, one hundred forty million, three hundred fifty-one thousand, one hundred thirty-one".