Base | Representation |
---|---|
bin | 11101111000001011100010… |
… | …100010011011011101010011 |
3 | 122020021002202210101220021212 |
4 | 131320023202202123131103 |
5 | 114210410423203130003 |
6 | 1143250102244210335 |
7 | 36451425235664621 |
oct | 3570134242333523 |
9 | 566232683356255 |
10 | 131404030130003 |
11 | 38962155348874 |
12 | 128a2b939999ab |
13 | 58424680cc967 |
14 | 2463dbbb22511 |
15 | 102d1c1430dd8 |
hex | 7782e289b753 |
131404030130003 has 6 divisors (see below), whose sum is σ = 135779606576532. Its totient is φ = 127165190447460.
The previous prime is 131404030129937. The next prime is 131404030130017. The reversal of 131404030130003 is 300031030404131.
It is not a de Polignac number, because 131404030130003 - 214 = 131404030113619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131404030130203) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 68368381001 + ... + 68368382922.
It is an arithmetic number, because the mean of its divisors is an integer number (22629934429422).
Almost surely, 2131404030130003 is an apocalyptic number.
131404030130003 is a deficient number, since it is larger than the sum of its proper divisors (4375576446529).
131404030130003 is an equidigital number, since it uses as much as digits as its factorization.
131404030130003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 136736763985 (or 136736763954 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 131404030130003 its reverse (300031030404131), we get a palindrome (431435060534134).
The spelling of 131404030130003 in words is "one hundred thirty-one trillion, four hundred four billion, thirty million, one hundred thirty thousand, three".
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