131404034201 has 4 divisors (see below), whose sum is σ = 143349855504. Its totient is φ = 119458212900.

The previous prime is 131404034191. The next prime is 131404034213. The reversal of 131404034201 is 102430404131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131404034201 - 2³⁴ = 114224165017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (131404034221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5972910635 + ... + 5972910656.

It is an arithmetic number, because the mean of its divisors is an integer number (35837463876).

Almost surely, 2^131404034201 is an apocalyptic number.

131404034201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131404034201 is a deficient number, since it is larger than the sum of its proper divisors (11945821303).

131404034201 is a wasteful number, since it uses less digits than its factorization.

131404034201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11945821302.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 131404034201 its reverse (102430404131), we get a palindrome (233834438332).

The spelling of 131404034201 in words is "one hundred thirty-one billion, four hundred four million, thirty-four thousand, two hundred one".