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13140420350411 = 36394736105313
BaseRepresentation
bin1011111100110111111000…
…0101100101000111001011
31201112012201111011102101102
42333031332011211013023
53210243040102203121
643540343100012015
72524235603031164
oct277157605450713
951465644142342
1013140420350411
114206903799372
12158285023100b
137441a0665763
14335ddd3d476b
1517bc2c23b90b
hexbf37e1651cb

13140420350411 has 4 divisors (see below), whose sum is σ = 13140456819672. Its totient is φ = 13140383881152.

The previous prime is 13140420350389. The next prime is 13140420350513. The reversal of 13140420350411 is 11405302404131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13140420350411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13140420350611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17688710 + ... + 18416603.

It is an arithmetic number, because the mean of its divisors is an integer number (3285114204918).

Almost surely, 213140420350411 is an apocalyptic number.

13140420350411 is a deficient number, since it is larger than the sum of its proper divisors (36469261).

13140420350411 is an equidigital number, since it uses as much as digits as its factorization.

13140420350411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36469260.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 13140420350411 its reverse (11405302404131), we get a palindrome (24545722754542).

The spelling of 13140420350411 in words is "thirteen trillion, one hundred forty billion, four hundred twenty million, three hundred fifty thousand, four hundred eleven".

Divisors: 1 363947 36105313 13140420350411