1314046351113 has 4 divisors (see below), whose sum is σ = 1752061801488. Its totient is φ = 876030900740.

The previous prime is 1314046351097. The next prime is 1314046351129. The reversal of 1314046351113 is 3111536404131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1314046351097) and next prime (1314046351129).

It is a cyclic number.

It is not a de Polignac number, because 1314046351113 - 2⁴ = 1314046351097 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1314046351133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219007725183 + ... + 219007725188.

It is an arithmetic number, because the mean of its divisors is an integer number (438015450372).

Almost surely, 2^{1314046351113} is an apocalyptic number.

It is an amenable number.

1314046351113 is a deficient number, since it is larger than the sum of its proper divisors (438015450375).

1314046351113 is an equidigital number, since it uses as much as digits as its factorization.

1314046351113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 438015450374.

The product of its (nonzero) digits is 12960, while the sum is 33.

The spelling of 1314046351113 in words is "one trillion, three hundred fourteen billion, forty-six million, three hundred fifty-one thousand, one hundred thirteen".