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13140500400145 = 511867221462887
BaseRepresentation
bin1011111100111000001011…
…0110111100100000010001
31201112012221001210100222101
42333032002312330200101
53210243221100301040
643540355035440401
72524240564322266
oct277160266744021
951465831710871
1013140500400145
1142069449a3978
121582872bb6101
137441b4112671
14336009cb126d
1517bc342a009a
hexbf382dbc811

13140500400145 has 8 divisors (see below), whose sum is σ = 15769929328704. Its totient is φ = 10511514421104.

The previous prime is 13140500400113. The next prime is 13140500400151. The reversal of 13140500400145 is 54100400504131.

13140500400145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13140500400145 - 25 = 13140500400113 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 110672109 + ... + 110790778.

It is an arithmetic number, because the mean of its divisors is an integer number (1971241166088).

Almost surely, 213140500400145 is an apocalyptic number.

It is an amenable number.

13140500400145 is a deficient number, since it is larger than the sum of its proper divisors (2629428928559).

13140500400145 is a wasteful number, since it uses less digits than its factorization.

13140500400145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221474759.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 13140500400145 its reverse (54100400504131), we get a palindrome (67240900904276).

The spelling of 13140500400145 in words is "thirteen trillion, one hundred forty billion, five hundred million, four hundred thousand, one hundred forty-five".

Divisors: 1 5 11867 59335 221462887 1107314435 2628100080029 13140500400145