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1314102540403 = 23373153176657
BaseRepresentation
bin10011000111110110100…
…111010111100001110011
311122121221001202201210101
4103013312213113201303
5133012240222243103
62443405042013231
7163640454202462
oct23076647274163
94577831681711
101314102540403
11467342697564
12192822347217
1396bc4a291c3
14478625149d9
15242b2060a1d
hex131f69d7873

1314102540403 has 8 divisors (see below), whose sum is σ = 1374913682208. Its totient is φ = 1253597752704.

The previous prime is 1314102540397. The next prime is 1314102540409. The reversal of 1314102540403 is 3040452014131.

It is an interprime number because it is at equal distance from previous prime (1314102540397) and next prime (1314102540409).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1314102540403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1314102540409) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 76579750 + ... + 76596907.

It is an arithmetic number, because the mean of its divisors is an integer number (171864210276).

Almost surely, 21314102540403 is an apocalyptic number.

1314102540403 is a deficient number, since it is larger than the sum of its proper divisors (60811141805).

1314102540403 is a wasteful number, since it uses less digits than its factorization.

1314102540403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 153177053.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 1314102540403 its reverse (3040452014131), we get a palindrome (4354554554534).

The spelling of 1314102540403 in words is "one trillion, three hundred fourteen billion, one hundred two million, five hundred forty thousand, four hundred three".

Divisors: 1 23 373 8579 153176657 3523063111 57134893061 1314102540403