Base | Representation |
---|---|
bin | 10011000111110110100… |
… | …111010111100001110011 |
3 | 11122121221001202201210101 |
4 | 103013312213113201303 |
5 | 133012240222243103 |
6 | 2443405042013231 |
7 | 163640454202462 |
oct | 23076647274163 |
9 | 4577831681711 |
10 | 1314102540403 |
11 | 467342697564 |
12 | 192822347217 |
13 | 96bc4a291c3 |
14 | 478625149d9 |
15 | 242b2060a1d |
hex | 131f69d7873 |
1314102540403 has 8 divisors (see below), whose sum is σ = 1374913682208. Its totient is φ = 1253597752704.
The previous prime is 1314102540397. The next prime is 1314102540409. The reversal of 1314102540403 is 3040452014131.
It is an interprime number because it is at equal distance from previous prime (1314102540397) and next prime (1314102540409).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314102540403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1314102540409) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 76579750 + ... + 76596907.
It is an arithmetic number, because the mean of its divisors is an integer number (171864210276).
Almost surely, 21314102540403 is an apocalyptic number.
1314102540403 is a deficient number, since it is larger than the sum of its proper divisors (60811141805).
1314102540403 is a wasteful number, since it uses less digits than its factorization.
1314102540403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153177053.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 1314102540403 its reverse (3040452014131), we get a palindrome (4354554554534).
The spelling of 1314102540403 in words is "one trillion, three hundred fourteen billion, one hundred two million, five hundred forty thousand, four hundred three".
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