1314113055531 has 4 divisors (see below), whose sum is σ = 1752150740712. Its totient is φ = 876075370352.

The previous prime is 1314113055529. The next prime is 1314113055557. The reversal of 1314113055531 is 1355503114131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314113055531 - 2¹ = 1314113055529 is a prime.

It is a super-2 number, since 2×1314113055531² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1314113055492 and 1314113055501.

It is not an unprimeable number, because it can be changed into a prime (1314113055131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219018842586 + ... + 219018842591.

It is an arithmetic number, because the mean of its divisors is an integer number (438037685178).

Almost surely, 2^{1314113055531} is an apocalyptic number.

1314113055531 is a deficient number, since it is larger than the sum of its proper divisors (438037685181).

1314113055531 is an equidigital number, since it uses as much as digits as its factorization.

1314113055531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 438037685180.

The product of its (nonzero) digits is 13500, while the sum is 33.

Adding to 1314113055531 its reverse (1355503114131), we get a palindrome (2669616169662).

The spelling of 1314113055531 in words is "one trillion, three hundred fourteen billion, one hundred thirteen million, fifty-five thousand, five hundred thirty-one".