1314121210401 has 4 divisors (see below), whose sum is σ = 1752161613872. Its totient is φ = 876080806932.

The previous prime is 1314121210357. The next prime is 1314121210439. The reversal of 1314121210401 is 1040121214131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1314121210401 - 2¹⁰ = 1314121209377 is a prime.

It is a super-3 number, since 3×1314121210401³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1314121210201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219020201731 + ... + 219020201736.

It is an arithmetic number, because the mean of its divisors is an integer number (438040403468).

Almost surely, 2^{1314121210401} is an apocalyptic number.

It is an amenable number.

1314121210401 is a deficient number, since it is larger than the sum of its proper divisors (438040403471).

1314121210401 is an equidigital number, since it uses as much as digits as its factorization.

1314121210401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 438040403470.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 1314121210401 its reverse (1040121214131), we get a palindrome (2354242424532).

The spelling of 1314121210401 in words is "one trillion, three hundred fourteen billion, one hundred twenty-one million, two hundred ten thousand, four hundred one".