Base | Representation |
---|---|
bin | 11000011110100011… |
… | …10000001101010001 |
3 | 1020220211111211200212 |
4 | 30033101300031101 |
5 | 203403122322113 |
6 | 10011553453505 |
7 | 643436322233 |
oct | 141721601521 |
9 | 36824454625 |
10 | 13141214033 |
11 | 5633966672 |
12 | 2668b71295 |
13 | 13157157bc |
14 | 8c9408253 |
15 | 51da480a8 |
hex | 30f470351 |
13141214033 has 4 divisors (see below), whose sum is σ = 13160741028. Its totient is φ = 13121687040.
The previous prime is 13141214029. The next prime is 13141214069. The reversal of 13141214033 is 33041214131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5278313104 + 7862900929 = 72652^2 + 88673^2 .
It is a cyclic number.
It is not a de Polignac number, because 13141214033 - 22 = 13141214029 is a prime.
It is a super-2 number, since 2×131412140332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13141214833) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9762488 + ... + 9763833.
It is an arithmetic number, because the mean of its divisors is an integer number (3290185257).
Almost surely, 213141214033 is an apocalyptic number.
It is an amenable number.
13141214033 is a deficient number, since it is larger than the sum of its proper divisors (19526995).
13141214033 is an equidigital number, since it uses as much as digits as its factorization.
13141214033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19526994.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 13141214033 its reverse (33041214131), we get a palindrome (46182428164).
The spelling of 13141214033 in words is "thirteen billion, one hundred forty-one million, two hundred fourteen thousand, thirty-three".
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