Base | Representation |
---|---|
bin | 1011111100111010111011… |
… | …1110010011001011110011 |
3 | 1201112021211122110122011121 |
4 | 2333032232332103023303 |
5 | 3210301230033304210 |
6 | 43541000315123111 |
7 | 2524265122303312 |
oct | 277165676231363 |
9 | 51467748418147 |
10 | 13141240525555 |
11 | 420719475a06a |
12 | 1582a3aa43497 |
13 | 7442a15606ac |
14 | 33607a2d2279 |
15 | 17bc7924b6da |
hex | bf3aef932f3 |
13141240525555 has 8 divisors (see below), whose sum is σ = 15882938190000. Its totient is φ = 10437359380896.
The previous prime is 13141240525453. The next prime is 13141240525603. The reversal of 13141240525555 is 55552504214131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13141240525555 - 211 = 13141240523507 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9454129180 + ... + 9454130569.
It is an arithmetic number, because the mean of its divisors is an integer number (1985367273750).
Almost surely, 213141240525555 is an apocalyptic number.
13141240525555 is a deficient number, since it is larger than the sum of its proper divisors (2741697664445).
13141240525555 is a wasteful number, since it uses less digits than its factorization.
13141240525555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18908259893.
The product of its (nonzero) digits is 600000, while the sum is 43.
Adding to 13141240525555 its reverse (55552504214131), we get a palindrome (68693744739686).
The spelling of 13141240525555 in words is "thirteen trillion, one hundred forty-one billion, two hundred forty million, five hundred twenty-five thousand, five hundred fifty-five".
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