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131413100200003 = 791663456964557
BaseRepresentation
bin11101111000010011111111…
…001010000000000001000011
3122020021222011220100012021101
4131320103333022000001003
5114211033012122400003
61143254202251235231
736452166062213446
oct3570237712000103
9566258156305241
10131413100200003
1138965a8a148696
12128a48a5448b17
13584328224459b
1424645dc57765d
15102d55284e11d
hex7784ff280043

131413100200003 has 4 divisors (see below), whose sum is σ = 133076557164640. Its totient is φ = 129749643235368.

The previous prime is 131413100200001. The next prime is 131413100200051. The reversal of 131413100200003 is 300002001314131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131413100200003 - 21 = 131413100200001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131413100200001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 831728482200 + ... + 831728482357.

It is an arithmetic number, because the mean of its divisors is an integer number (33269139291160).

Almost surely, 2131413100200003 is an apocalyptic number.

131413100200003 is a deficient number, since it is larger than the sum of its proper divisors (1663456964637).

131413100200003 is an equidigital number, since it uses as much as digits as its factorization.

131413100200003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1663456964636.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 131413100200003 its reverse (300002001314131), we get a palindrome (431415101514134).

The spelling of 131413100200003 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred million, two hundred thousand, three".

Divisors: 1 79 1663456964557 131413100200003