Base | Representation |
---|---|
bin | 111101001100011010… |
… | …1001111110111111001 |
3 | 110120012101221220002202 |
4 | 1322120311033313321 |
5 | 4123113224124421 |
6 | 140211555035545 |
7 | 12331353020204 |
oct | 1723065176771 |
9 | 416171856082 |
10 | 131413114361 |
11 | 50806305941 |
12 | 21575b9bbb5 |
13 | c513895589 |
14 | 650903293b |
15 | 3641e4910b |
hex | 1e98d4fdf9 |
131413114361 has 4 divisors (see below), whose sum is σ = 131414117712. Its totient is φ = 131412111012.
The previous prime is 131413114309. The next prime is 131413114367. The reversal of 131413114361 is 163411314131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131413114361 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (131413114367) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 269351 + ... + 579116.
It is an arithmetic number, because the mean of its divisors is an integer number (32853529428).
Almost surely, 2131413114361 is an apocalyptic number.
It is an amenable number.
131413114361 is a deficient number, since it is larger than the sum of its proper divisors (1003351).
131413114361 is an equidigital number, since it uses as much as digits as its factorization.
131413114361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1003350.
The product of its digits is 2592, while the sum is 29.
Adding to 131413114361 its reverse (163411314131), we get a palindrome (294824428492).
The spelling of 131413114361 in words is "one hundred thirty-one billion, four hundred thirteen million, one hundred fourteen thousand, three hundred sixty-one".
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