Base | Representation |
---|---|
bin | 1011111100111011001101… |
… | …0111101111101111110011 |
3 | 1201112022000210022000120001 |
4 | 2333032303113233233303 |
5 | 3210301402430230021 |
6 | 43541011512330431 |
7 | 2524300006360624 |
oct | 277166327575763 |
9 | 51468023260501 |
10 | 13141314305011 |
11 | 4207222371722 |
12 | 1582a5b6a3a17 |
13 | 7442b3923589 |
14 | 336086019a4b |
15 | 17bc80972091 |
hex | bf3b35efbf3 |
13141314305011 has 4 divisors (see below), whose sum is σ = 13170978671832. Its totient is φ = 13111649938192.
The previous prime is 13141314304999. The next prime is 13141314305047. The reversal of 13141314305011 is 11050341314131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13141314305011 - 27 = 13141314304883 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13141314305071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14832182746 + ... + 14832183631.
It is an arithmetic number, because the mean of its divisors is an integer number (3292744667958).
Almost surely, 213141314305011 is an apocalyptic number.
13141314305011 is a deficient number, since it is larger than the sum of its proper divisors (29664366821).
13141314305011 is an equidigital number, since it uses as much as digits as its factorization.
13141314305011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29664366820.
The product of its (nonzero) digits is 2160, while the sum is 28.
Adding to 13141314305011 its reverse (11050341314131), we get a palindrome (24191655619142).
The spelling of 13141314305011 in words is "thirteen trillion, one hundred forty-one billion, three hundred fourteen million, three hundred five thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •