131413330104401 has 4 divisors (see below), whose sum is σ = 131413395425904. Its totient is φ = 131413264782900.

The previous prime is 131413330104389. The next prime is 131413330104409. The reversal of 131413330104401 is 104401033314131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131413330104401 - 2³⁸ = 131138452197457 is a prime.

It is a super-2 number, since 2×131413330104401² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (131413330104409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29543915 + ... + 33699696.

It is an arithmetic number, because the mean of its divisors is an integer number (32853348856476).

Almost surely, 2^{131413330104401} is an apocalyptic number.

It is an amenable number.

131413330104401 is a deficient number, since it is larger than the sum of its proper divisors (65321503).

131413330104401 is an equidigital number, since it uses as much as digits as its factorization.

131413330104401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65321502.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131413330104401 its reverse (104401033314131), we get a palindrome (235814363418532).

The spelling of 131413330104401 in words is "one hundred thirty-one trillion, four hundred thirteen billion, three hundred thirty million, one hundred four thousand, four hundred one".