Base | Representation |
---|---|
bin | 1011111100111011010101… |
… | …1111111111100110110011 |
3 | 1201112022010021111121110000 |
4 | 2333032311133333212303 |
5 | 3210301441101142210 |
6 | 43541015230041043 |
7 | 2524300622065530 |
oct | 277166537774663 |
9 | 51468107447400 |
10 | 13141350021555 |
11 | 4207240547028 |
12 | 1582a6b649183 |
13 | 7442bb14a522 |
14 | 33608aa75d87 |
15 | 17bc83b79ac0 |
hex | bf3b57ff9b3 |
13141350021555 has 80 divisors (see below), whose sum is σ = 26924256463104. Its totient is φ = 6007056655680.
The previous prime is 13141350021523. The next prime is 13141350021593. The reversal of 13141350021555 is 55512005314131.
13141350021555 is a `hidden beast` number, since 1 + 3 + 1 + 41 + 350 + 0 + 215 + 55 = 666.
It is not a de Polignac number, because 13141350021555 - 25 = 13141350021523 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 42629404 + ... + 42936566.
Almost surely, 213141350021555 is an apocalyptic number.
13141350021555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13141350021555 is an abundant number, since it is smaller than the sum of its proper divisors (13782906441549).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13141350021555 is a wasteful number, since it uses less digits than its factorization.
13141350021555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 322278 (or 322269 counting only the distinct ones).
The product of its (nonzero) digits is 45000, while the sum is 36.
Adding to 13141350021555 its reverse (55512005314131), we get a palindrome (68653355335686).
The spelling of 13141350021555 in words is "thirteen trillion, one hundred forty-one billion, three hundred fifty million, twenty-one thousand, five hundred fifty-five".
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