131420113 has 4 divisors (see below), whose sum is σ = 143367408. Its totient is φ = 119472820.

The previous prime is 131420111. The next prime is 131420143. The reversal of 131420113 is 311024131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311024131 = 11 ⋅28274921.

It is a cyclic number.

It is not a de Polignac number, because 131420113 - 2¹ = 131420111 is a prime.

It is a super-2 number, since 2×131420113² = 34542492201865538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131420111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5973631 + ... + 5973652.

It is an arithmetic number, because the mean of its divisors is an integer number (35841852).

Almost surely, 2^131420113 is an apocalyptic number.

It is an amenable number.

131420113 is a deficient number, since it is larger than the sum of its proper divisors (11947295).

131420113 is a wasteful number, since it uses less digits than its factorization.

131420113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11947294.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 131420113 is about 11463.8611732697. The cubic root of 131420113 is about 508.4176420109.

Adding to 131420113 its reverse (311024131), we get a palindrome (442444244).

The spelling of 131420113 in words is "one hundred thirty-one million, four hundred twenty thousand, one hundred thirteen".