13142023143131 has 4 divisors (see below), whose sum is σ = 13184010437832. Its totient is φ = 13100035848432.

The previous prime is 13142023143103. The next prime is 13142023143233. The reversal of 13142023143131 is 13134132024131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13142023143131 - 2²⁶ = 13141956034267 is a prime.

It is a super-2 number, since 2×13142023143131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13142023143094 and 13142023143103.

It is not an unprimeable number, because it can be changed into a prime (13142023143631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20993646881 + ... + 20993647506.

It is an arithmetic number, because the mean of its divisors is an integer number (3296002609458).

Almost surely, 2^{13142023143131} is an apocalyptic number.

13142023143131 is a deficient number, since it is larger than the sum of its proper divisors (41987294701).

13142023143131 is an equidigital number, since it uses as much as digits as its factorization.

13142023143131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41987294700.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13142023143131 its reverse (13134132024131), we get a palindrome (26276155167262).

The spelling of 13142023143131 in words is "thirteen trillion, one hundred forty-two billion, twenty-three million, one hundred forty-three thousand, one hundred thirty-one".