Base | Representation |
---|---|
bin | 11000011110101010… |
… | …01001100000110001 |
3 | 1020220220012001122210 |
4 | 30033111021200301 |
5 | 203403334312423 |
6 | 10012024522333 |
7 | 643450020225 |
oct | 141725114061 |
9 | 36826161583 |
10 | 13142104113 |
11 | 5634414376 |
12 | 26693203a9 |
13 | 1315967988 |
14 | 8c959a785 |
15 | 51db71b93 |
hex | 30f549831 |
13142104113 has 12 divisors (see below), whose sum is σ = 18317793200. Its totient is φ = 8380471176.
The previous prime is 13142104081. The next prime is 13142104141. The reversal of 13142104113 is 31140124131.
It is not a de Polignac number, because 13142104113 - 25 = 13142104081 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 13142104113.
It is not an unprimeable number, because it can be changed into a prime (13142104193) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4138963 + ... + 4142136.
Almost surely, 213142104113 is an apocalyptic number.
It is an amenable number.
13142104113 is a deficient number, since it is larger than the sum of its proper divisors (5175689087).
13142104113 is an equidigital number, since it uses as much as digits as its factorization.
13142104113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8281148 (or 8281125 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 13142104113 its reverse (31140124131), we get a palindrome (44282228244).
The spelling of 13142104113 in words is "thirteen billion, one hundred forty-two million, one hundred four thousand, one hundred thirteen".
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