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1314211052051 = 3783427942381
BaseRepresentation
bin10011000111111101000…
…101010011101000010011
311122122012121221200210022
4103013331011103220103
5133013001012131201
62443423515454055
7163643242425122
oct23077505235023
94578177850708
101314211052051
11467398971a07
1219285275732b
1396c1135cc91
1447872abdab9
15242bb84741b
hex131fd153a13

1314211052051 has 8 divisors (see below), whose sum is σ = 1365992083344. Its totient is φ = 1263285905760.

The previous prime is 1314211052029. The next prime is 1314211052053. The reversal of 1314211052051 is 1502501124131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1314211052051 - 214 = 1314211035667 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1314211052051.

It is not an unprimeable number, because it can be changed into a prime (1314211052053) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 213968120 + ... + 213974261.

It is an arithmetic number, because the mean of its divisors is an integer number (170749010418).

Almost surely, 21314211052051 is an apocalyptic number.

1314211052051 is a deficient number, since it is larger than the sum of its proper divisors (51781031293).

1314211052051 is an equidigital number, since it uses as much as digits as its factorization.

1314211052051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 427942501.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 1314211052051 its reverse (1502501124131), we get a palindrome (2816712176182).

The spelling of 1314211052051 in words is "one trillion, three hundred fourteen billion, two hundred eleven million, fifty-two thousand, fifty-one".

Divisors: 1 37 83 3071 427942381 15833868097 35519217623 1314211052051