131421215200531 has 4 divisors (see below), whose sum is σ = 131422490631000. Its totient is φ = 131419939770064.

The previous prime is 131421215200529. The next prime is 131421215200547. The reversal of 131421215200531 is 135002512124131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131421215200531 - 2¹ = 131421215200529 is a prime.

It is a super-2 number, since 2×131421215200531² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131421215200493 and 131421215200502.

It is not an unprimeable number, because it can be changed into a prime (131421215206531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 637560661 + ... + 637766758.

It is an arithmetic number, because the mean of its divisors is an integer number (32855622657750).

Almost surely, 2^{131421215200531} is an apocalyptic number.

131421215200531 is a deficient number, since it is larger than the sum of its proper divisors (1275430469).

131421215200531 is a wasteful number, since it uses less digits than its factorization.

131421215200531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1275430468.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 131421215200531 its reverse (135002512124131), we get a palindrome (266423727324662).

The spelling of 131421215200531 in words is "one hundred thirty-one trillion, four hundred twenty-one billion, two hundred fifteen million, two hundred thousand, five hundred thirty-one".