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13142132431411 = 43305630986777
BaseRepresentation
bin1011111100111110010000…
…1000101001101000110011
31201112101010210202010222211
42333033210020221220303
53210310041400301121
643541225015512551
72524326202341034
oct277174410515063
951471123663884
1013142132431411
114207602163145
121583049688757
137443b4281b39
14336122942a8b
1517bccc6c9ce1
hexbf3e4229a33

13142132431411 has 4 divisors (see below), whose sum is σ = 13447763418232. Its totient is φ = 12836501444592.

The previous prime is 13142132431409. The next prime is 13142132431423. The reversal of 13142132431411 is 11413423124131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13142132431411 - 21 = 13142132431409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13142132431481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152815493346 + ... + 152815493431.

It is an arithmetic number, because the mean of its divisors is an integer number (3361940854558).

Almost surely, 213142132431411 is an apocalyptic number.

13142132431411 is a deficient number, since it is larger than the sum of its proper divisors (305630986821).

13142132431411 is an equidigital number, since it uses as much as digits as its factorization.

13142132431411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 305630986820.

The product of its digits is 6912, while the sum is 31.

Adding to 13142132431411 its reverse (11413423124131), we get a palindrome (24555555555542).

The spelling of 13142132431411 in words is "thirteen trillion, one hundred forty-two billion, one hundred thirty-two million, four hundred thirty-one thousand, four hundred eleven".

Divisors: 1 43 305630986777 13142132431411