Base | Representation |
---|---|
bin | 11101111000011100100100… |
… | …111100100011000100001001 |
3 | 122020022211222201211000102112 |
4 | 131320130210330203010021 |
5 | 114211210404440023340 |
6 | 1143302325432312105 |
7 | 36452643464350565 |
oct | 3570344474430411 |
9 | 566284881730375 |
10 | 131422324142345 |
11 | 38969992895035 |
12 | 128a663a542635 |
13 | 58440c2212832 |
14 | 2464c356046a5 |
15 | 102d8e2514065 |
hex | 778724f23109 |
131422324142345 has 4 divisors (see below), whose sum is σ = 157706788970820. Its totient is φ = 105137859313872.
The previous prime is 131422324142339. The next prime is 131422324142429. The reversal of 131422324142345 is 543241423224131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 14806342105801 + 116615982036544 = 3847901^2 + 10798888^2 .
It is a cyclic number.
It is not a de Polignac number, because 131422324142345 - 220 = 131422323093769 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13142232414230 + ... + 13142232414239.
It is an arithmetic number, because the mean of its divisors is an integer number (39426697242705).
Almost surely, 2131422324142345 is an apocalyptic number.
It is an amenable number.
131422324142345 is a deficient number, since it is larger than the sum of its proper divisors (26284464828475).
131422324142345 is an equidigital number, since it uses as much as digits as its factorization.
131422324142345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26284464828474.
The product of its digits is 552960, while the sum is 41.
Adding to 131422324142345 its reverse (543241423224131), we get a palindrome (674663747366476).
The spelling of 131422324142345 in words is "one hundred thirty-one trillion, four hundred twenty-two billion, three hundred twenty-four million, one hundred forty-two thousand, three hundred forty-five".
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