131422413210401 has 4 divisors (see below), whose sum is σ = 132457235361792. Its totient is φ = 130387591059012.

The previous prime is 131422413210397. The next prime is 131422413210449. The reversal of 131422413210401 is 104012314224131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131422413210401 - 2² = 131422413210397 is a prime.

It is a super-3 number, since 3×131422413210401³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131422413210701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 517411075505 + ... + 517411075758.

It is an arithmetic number, because the mean of its divisors is an integer number (33114308840448).

Almost surely, 2^{131422413210401} is an apocalyptic number.

It is an amenable number.

131422413210401 is a deficient number, since it is larger than the sum of its proper divisors (1034822151391).

131422413210401 is a wasteful number, since it uses less digits than its factorization.

131422413210401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1034822151390.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 131422413210401 its reverse (104012314224131), we get a palindrome (235434727434532).

The spelling of 131422413210401 in words is "one hundred thirty-one trillion, four hundred twenty-two billion, four hundred thirteen million, two hundred ten thousand, four hundred one".