131422413304441 has 4 divisors (see below), whose sum is σ = 150197043776512. Its totient is φ = 112647782832372.

The previous prime is 131422413304363. The next prime is 131422413304447. The reversal of 131422413304441 is 144403314224131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131422413304441 - 2³¹ = 131420265820793 is a prime.

It is a super-3 number, since 3×131422413304441³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131422413304441.

It is not an unprimeable number, because it can be changed into a prime (131422413304447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9387315236025 + ... + 9387315236038.

It is an arithmetic number, because the mean of its divisors is an integer number (37549260944128).

Almost surely, 2^{131422413304441} is an apocalyptic number.

It is an amenable number.

131422413304441 is a deficient number, since it is larger than the sum of its proper divisors (18774630472071).

131422413304441 is an equidigital number, since it uses as much as digits as its factorization.

131422413304441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18774630472070.

The product of its (nonzero) digits is 110592, while the sum is 37.

Adding to 131422413304441 its reverse (144403314224131), we get a palindrome (275825727528572).

The spelling of 131422413304441 in words is "one hundred thirty-one trillion, four hundred twenty-two billion, four hundred thirteen million, three hundred four thousand, four hundred forty-one".