Base | Representation |
---|---|
bin | 11000011110101011… |
… | …10000001111011011 |
3 | 1020220220111010021010 |
4 | 30033111300033123 |
5 | 203403404401442 |
6 | 10012032145003 |
7 | 643451250555 |
oct | 141725601733 |
9 | 36826433233 |
10 | 13142262747 |
11 | 5634512579 |
12 | 2669398163 |
13 | 13159c1c43 |
14 | 8c95dc4d5 |
15 | 51dba3b9c |
hex | 30f5703db |
13142262747 has 4 divisors (see below), whose sum is σ = 17523017000. Its totient is φ = 8761508496.
The previous prime is 13142262739. The next prime is 13142262751. The reversal of 13142262747 is 74726224131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13142262747 - 23 = 13142262739 is a prime.
It is a super-2 number, since 2×131422627472 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13142262737) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2190377122 + ... + 2190377127.
It is an arithmetic number, because the mean of its divisors is an integer number (4380754250).
Almost surely, 213142262747 is an apocalyptic number.
13142262747 is a deficient number, since it is larger than the sum of its proper divisors (4380754253).
13142262747 is an equidigital number, since it uses as much as digits as its factorization.
13142262747 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4380754252.
The product of its digits is 112896, while the sum is 39.
Adding to 13142262747 its reverse (74726224131), we get a palindrome (87868486878).
The spelling of 13142262747 in words is "thirteen billion, one hundred forty-two million, two hundred sixty-two thousand, seven hundred forty-seven".
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