Base | Representation |
---|---|
bin | 1011111100111110111001… |
… | …1001000011000101101011 |
3 | 1201112101120210112020122011 |
4 | 2333033232121003011223 |
5 | 3210310414423031443 |
6 | 43541254043540351 |
7 | 2524333362042646 |
oct | 277175631030553 |
9 | 51471523466564 |
10 | 13142304502123 |
11 | 42076902aa445 |
12 | 158309722a6b7 |
13 | 744410b0a824 |
14 | 33613b734a5d |
15 | 17bcdc868b9d |
hex | bf3ee64316b |
13142304502123 has 16 divisors (see below), whose sum is σ = 14228336378880. Its totient is φ = 12094085667456.
The previous prime is 13142304502079. The next prime is 13142304502207. The reversal of 13142304502123 is 32120540324131.
It is not a de Polignac number, because 13142304502123 - 213 = 13142304493931 is a prime.
It is a super-3 number, since 3×131423045021233 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13142304542123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47365465 + ... + 47642122.
It is an arithmetic number, because the mean of its divisors is an integer number (889271023680).
Almost surely, 213142304502123 is an apocalyptic number.
13142304502123 is a deficient number, since it is larger than the sum of its proper divisors (1086031876757).
13142304502123 is a wasteful number, since it uses less digits than its factorization.
13142304502123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95007786.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13142304502123 its reverse (32120540324131), we get a palindrome (45262844826254).
The spelling of 13142304502123 in words is "thirteen trillion, one hundred forty-two billion, three hundred four million, five hundred two thousand, one hundred twenty-three".
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