Base | Representation |
---|---|
bin | 1011111100111110111001… |
… | …1001000011100011110011 |
3 | 1201112101120210112100021120 |
4 | 2333033232121003203303 |
5 | 3210310414423112201 |
6 | 43541254043553323 |
7 | 2524333362051402 |
oct | 277175631034363 |
9 | 51471523470246 |
10 | 13142304504051 |
11 | 4207690300938 |
12 | 158309722b843 |
13 | 744410b0b678 |
14 | 33613b735639 |
15 | 17bcdc869536 |
hex | bf3ee6438f3 |
13142304504051 has 8 divisors (see below), whose sum is σ = 17534809498320. Its totient is φ = 8755667922912.
The previous prime is 13142304504037. The next prime is 13142304504053. The reversal of 13142304504051 is 15040540324131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13142304504051 - 217 = 13142304372979 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13142304504053) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1467098056 + ... + 1467107013.
It is an arithmetic number, because the mean of its divisors is an integer number (2191851187290).
Almost surely, 213142304504051 is an apocalyptic number.
13142304504051 is a deficient number, since it is larger than the sum of its proper divisors (4392504994269).
13142304504051 is a wasteful number, since it uses less digits than its factorization.
13142304504051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2934206565.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 13142304504051 its reverse (15040540324131), we get a palindrome (28182844828182).
The spelling of 13142304504051 in words is "thirteen trillion, one hundred forty-two billion, three hundred four million, five hundred four thousand, fifty-one".
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