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13142304504051 = 314932934205069
BaseRepresentation
bin1011111100111110111001…
…1001000011100011110011
31201112101120210112100021120
42333033232121003203303
53210310414423112201
643541254043553323
72524333362051402
oct277175631034363
951471523470246
1013142304504051
114207690300938
12158309722b843
13744410b0b678
1433613b735639
1517bcdc869536
hexbf3ee6438f3

13142304504051 has 8 divisors (see below), whose sum is σ = 17534809498320. Its totient is φ = 8755667922912.

The previous prime is 13142304504037. The next prime is 13142304504053. The reversal of 13142304504051 is 15040540324131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13142304504051 - 217 = 13142304372979 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13142304504053) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1467098056 + ... + 1467107013.

It is an arithmetic number, because the mean of its divisors is an integer number (2191851187290).

Almost surely, 213142304504051 is an apocalyptic number.

13142304504051 is a deficient number, since it is larger than the sum of its proper divisors (4392504994269).

13142304504051 is a wasteful number, since it uses less digits than its factorization.

13142304504051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2934206565.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 13142304504051 its reverse (15040540324131), we get a palindrome (28182844828182).

The spelling of 13142304504051 in words is "thirteen trillion, one hundred forty-two billion, three hundred four million, five hundred four thousand, fifty-one".

Divisors: 1 3 1493 4479 2934205069 8802615207 4380768168017 13142304504051