131423131104043 has 4 divisors (see below), whose sum is σ = 133006542322248. Its totient is φ = 129839719885840.

The previous prime is 131423131104037. The next prime is 131423131104053. The reversal of 131423131104043 is 340401131324131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131423131104043 is a prime.

It is a super-3 number, since 3×131423131104043³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131423131103996 and 131423131104014.

It is not an unprimeable number, because it can be changed into a prime (131423131104053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 791705608978 + ... + 791705609143.

It is an arithmetic number, because the mean of its divisors is an integer number (33251635580562).

Almost surely, 2^{131423131104043} is an apocalyptic number.

131423131104043 is a deficient number, since it is larger than the sum of its proper divisors (1583411218205).

131423131104043 is an equidigital number, since it uses as much as digits as its factorization.

131423131104043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1583411218204.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 131423131104043 its reverse (340401131324131), we get a palindrome (471824262428174).

The spelling of 131423131104043 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred thirty-one million, one hundred four thousand, forty-three".